問(wèn)題描述

var arr = [ { ServiceID: ’go-storage-127.0.0.1-8080-9090’, ServiceName: ’storage’, }, { ServiceID: ’System-xxx-192.168.0.111-8000-8000’, ServiceName: ’xxx’, }, { ServiceID: ’System-xxx2-192.168.0.111-8000-8000’, ServiceName: ’xxx2’, }, { ServiceID: ’System-xxx3-192.168.0.111-8000-8000’, ServiceName: ’xxx3’, }, {ServiceID: ’System2-xxx3-192.168.0.111-8000-8000’,ServiceName: ’xxx3’, }, {ServiceID: ’test-xxx3-192.168.0.111-8000-8000’,ServiceName: ’xxx3’,}];

將arr數(shù)組中ServiceID以test或者System開(kāi)頭的數(shù)組元素刪掉 用刪掉的方法總是沒(méi)法講匹配到的全刪，哪位高手能幫個(gè)忙呢？謝謝！

問(wèn)題解答

arr = arr.filter(item => !(/^test|^System/i.test(item.ServiceID)))

var startsWithArr = strArr => str => { return strArr.some(e => str.startsWith(e)); }var starts = startsWithArr([ ’test’, ’System-’]);var filterArr = arr => { arr.filter(e => !starts(e.ServiceID)); }回答3：

用Array.filter方法，將過(guò)濾后的數(shù)組賦值回arr；

arr = arr.filter(function(item) { return !(/^(test|System)/g.test(item.ServiceId || ’’));});